Re: Can I use Potassium Chloride or Potassium Sulphate as the coagulant for making Tofu ?Borek wrote:
> On Tue, 06 May 2008 08:38:03 +0200, Marshall Price <d021317c@yahoo . com >
> wrote:
>
>>>> By the way, Bob M has a discussion about phosphoric acid on his
>>>> website which confuses me:
>>>> * w w w .molab.co.nz/pages/cola-osteoporosis.php . Any comments on
>>>> how he gets "50%" -- and what he means by it?
>>> You mean 50% like in 50% neutralization? It means nothing. To get pH
>>> 5.5 you have to neutralize a little bit more than first proton, say
>>> 0.1M acid plus 0.105M NaOH. If the 50% refers to real 50% - you end
>>> with perfect pH=pKa2 buffer, that gives pH close to neutral (pKa2=7.2).
>
>> This is still way over my head. Could you elaborate a little more?
>
> Very generally speaking, phosphoric acid neutralization goes like that:
>
> H3PO4 + 3NaOH -> Na3PO4 + H2O
>
> 50% means that you add half the amount of NaOH required. This in turn
> means that you:
> 1. Proceed completely with first step of neutralization, ie
> H3PO4 + NaOH -> NaH2PO4 + H2O
> 2. Proceed 50% into the second step of neutralization:
> NaH2PO4 + NaOH = Na2HPO4 + H2O
>
> So, after 50% neutralization your solution is 50/50 H2PO4- and HPO4-2.
> This is a classic buffer solution, with pH described by so called
> Henderson-Hasselbalch equation, which in this particluar case takes form:
>
> pH = 7.2 + log([HPO4-2]/[H2PO4-])
>
> but we already know that [HPO4-2] = [H2PO4-] (remember, solution is
> 50/50). That leaves us with
>
> pH = 7.2
>
> There are fine details omitted and hidden assumptions done so nitpickers
> can bash almost every phrase in this post, but no matter how the'll try,
> their final pH will be around 7 as well.
>
> To get solution with pH around 5.5 you have to neutralize first proton and
> add very small excess of base. I would call it 35% neutralization
> (assuming 100% is when the amount of base is three times that of acid, to
> account for the phosphoric acid "triprocity").
>
> Now, you can define 100% neutralization in terms of single proton - ie
> 100% is when the reaction
>
> H3PO4 + NaOH -> NaH2PO4 + H2O
>
> is finished. That means full neutralization is 300%. This approach
> sometimes simplifies calculations. Still, 50% in this case is when you
> have 50/50 mixture af H3PO4 and H2PO4- - this is another buffer, with pH
> around 2.2. No matter how you try it is NOT 5.5.
>
> Browse pH calculation lectures at
>
> * w w w .chembuddy . com /?left=pH-calculation&right=toc
>
> if you need more. Or play with pH calculator from
>
> * w w w .chembuddy . com /?left=BATE&right=pH-calculator
>
> to see for yourself how the pH changes for different solutions. There is a
> 30 day free trial so you can do it for free.
>
> Borek
Wow. Thank you very much. (No wonder I didn't get it!)
When you say "full neutralization is 300%," is that because you need
three times as many molecules of NaOH (sodium hydroxide) as you have of
H3PO4 (phosphoric acid)? Why did you use NaOH in the example?
(Since I see phosphate groups so often in metabolic reactions, I was
surprised to read that the phosphoric acid in soft drinks might cause
problems.)
--
Marshall Price of Miami
Known to Yahoo as d021317c